Travail Et Energie — Quiz — Mouvement Rectiligne

✅ Quiz : Mouvement Rectiligne

Ce quiz contient 20 questions.

Note : Placeholder pour valider la structure. Le JSON converti est conservé ci-dessous pour l’import final des vraies questions Tutor LMS.

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{
  "quiz_title": "Mouvement Rectiligne",
  "quiz_slug": "02_mouvement_rectiligne_quiz",
  "quiz_description": "Quiz Edu509 : Mouvement Rectiligne",
  "quiz_settings": {
    "time_limit": {
      "time_value": 0,
      "time_type": "minutes"
    },
    "hide_quiz_time_display": false,
    "attempts_allowed": 0,
    "passing_grade": 70,
    "max_questions_for_answer": 0,
    "questions_order": "rand",
    "hide_question_number_overview": false,
    "short_answer_characters_limit": 200
  },
  "questions": [
    {
      "question_order": 1,
      "question_title": "Un objet se déplace en ligne droite à une vitesse constante de \\\\(12\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(10\\\\,\\\\mathrm{s}\\\\). Quelle distance parcourt-il ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRU, la distance parcourue est \\\\(x = x_0 + v t\\\\). Ici, \\\\(x_0 = 0\\\\), \\\\(v = 12\\\\,\\\\mathrm{m/s}\\\\), \\\\(t = 10\\\\,\\\\mathrm{s}\\\\). Donc \\\\(x = 0 + 12 \\\\times 10 = 120\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "120 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "24 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "1,2 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "100 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 2,
      "question_title": "Un cycliste démarre du repos et accélère à \\\\(1,5\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(8\\\\,\\\\mathrm{s}\\\\). Quelle est sa vitesse finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale en MRUA est \\\\(v = v_0 + a t\\\\). Ici, \\\\(v_0 = 0\\\\), \\\\(a = 1,5\\\\,\\\\mathrm{m/s^2}\\\\), \\\\(t = 8\\\\,\\\\mathrm{s}\\\\). Donc \\\\(v = 0 + 1,5 \\\\times 8 = 12\\\\,\\\\mathrm{m/s}\\\\).",
      "answers": [
        {
          "answer_title": "12 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "10 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "8 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "6 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 3,
      "question_title": "Un mobile part de la position \\\\(x_0 = 5\\\\,\\\\mathrm{m}\\\\) et avance à \\\\(3\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(7\\\\,\\\\mathrm{s}\\\\). Quelle est sa position finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRU, \\\\(x = x_0 + v t\\\\). Ici, \\\\(x_0 = 5\\\\), \\\\(v = 3\\\\), \\\\(t = 7\\\\). Donc \\\\(x = 5 + 3 \\\\times 7 = 26\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "26 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "21 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "17 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "12 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 4,
      "question_title": "Un objet lancé à \\\\(4,0\\\\,\\\\mathrm{m/s}\\\\) subit une accélération de \\\\(2,0\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(5,0\\\\,\\\\mathrm{s}\\\\). Quelle distance a-t-il parcourue ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRUA, \\\\(x = x_0 + v_0 t + \\\\frac{1}{2} a t^2\\\\). Ici, \\\\(x_0 = 0\\\\), \\\\(v_0 = 4,0\\\\), \\\\(a = 2,0\\\\), \\\\(t = 5,0\\\\). \\\\(x = 0 + 4,0 \\\\times 5,0 + 0,5 \\\\times 2,0 \\\\times 25 = 20 + 25 = 45\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "45 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "50 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "30 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "25 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 5,
      "question_title": "Un train freine avec une accélération constante de \\\\(-2,0\\\\,\\\\mathrm{m/s^2}\\\\) depuis \\\\(20\\\\,\\\\mathrm{m/s}\\\\) jusqu'à l'arrêt. Quelle distance parcourt-il avant de s'arrêter ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(x = x_0 + \\\\frac{v^2 - v_0^2}{2a}\\\\). Ici, \\\\(x_0 = 0\\\\), \\\\(v = 0\\\\), \\\\(v_0 = 20\\\\), \\\\(a = -2,0\\\\). \\\\(x = 0 + \\\\frac{0^2 - 20^2}{2 \\\\times -2,0} = \\\\frac{-400}{-4} = 100\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "100 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "200 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "50 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "20 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 6,
      "question_title": "Un objet part du repos et parcourt \\\\(36\\\\,\\\\mathrm{m}\\\\) en \\\\(6\\\\,\\\\mathrm{s}\\\\) avec accélération constante. Quelle est la valeur de son accélération ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRUA, \\\\(x = x_0 + v_0 t + \\\\frac{1}{2} a t^2\\\\). Ici, \\\\(x_0 = 0\\\\), \\\\(v_0 = 0\\\\), \\\\(x = 36\\\\), \\\\(t = 6\\\\). \\\\(36 = 0 + 0 + 0,5 a \\\\times 36\\\\). Donc \\\\(36 = 18a\\\\), donc \\\\(a = 2\\\\,\\\\mathrm{m/s^2}\\\\).",
      "answers": [
        {
          "answer_title": "2 m/s^2",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "1 m/s^2",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "3 m/s^2",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "4 m/s^2",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 7,
      "question_title": "Un coureur accélère de \\\\(2,5\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(4\\\\,\\\\mathrm{s}\\\\) à partir du repos. Quelle est sa vitesse finale et la distance parcourue ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Vitesse finale : \\\\(v = 0 + 2,5 \\\\times 4 = 10\\\\,\\\\mathrm{m/s}\\\\). Distance : \\\\(x = 0 + 0 + 0,5 \\\\times 2,5 \\\\times 16 = 20\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "10 m/s et 20 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "8 m/s et 16 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "12 m/s et 24 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "5 m/s et 10 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 8,
      "question_title": "Un objet se déplace à \\\\(15\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(0,5\\\\,\\\\mathrm{min}\\\\). Quelle distance parcourt-il ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Convertir \\\\(0,5\\\\,\\\\mathrm{min} = 30\\\\,\\\\mathrm{s}\\\\). \\\\(x = 0 + 15 \\\\times 30 = 450\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "450 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "30 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "7,5 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "75 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 9,
      "question_title": "Un objet a une vitesse initiale de \\\\(6\\\\,\\\\mathrm{m/s}\\\\) et accélère à \\\\(3\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(2\\\\,\\\\mathrm{s}\\\\). Quelle est sa vitesse finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Vitesse finale : \\\\(v = 6 + 3 \\\\times 2 = 12\\\\,\\\\mathrm{m/s}\\\\).",
      "answers": [
        {
          "answer_title": "12 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "9 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "6 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "15 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 10,
      "question_title": "Un mobile part de \\\\(x_0 = 2\\\\,\\\\mathrm{m}\\\\), avance à \\\\(5\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(4\\\\,\\\\mathrm{s}\\\\). Quelle est sa position finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRU, \\\\(x = x_0 + v t = 2 + 5 \\\\times 4 = 22\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "22 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "20 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "18 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "10 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 11,
      "question_title": "Un objet lancé à \\\\(10\\\\,\\\\mathrm{m/s}\\\\) subit une accélération de \\\\(-2\\\\,\\\\mathrm{m/s^2}\\\\). Combien de temps met-il pour s’arrêter ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(v = v_0 + a t\\\\). \\\\(0 = 10 - 2t\\\\) donc \\\\(t = 5\\\\,\\\\mathrm{s}\\\\).",
      "answers": [
        {
          "answer_title": "5 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "10 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "2 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "20 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 12,
      "question_title": "Un objet part du repos et atteint \\\\(16\\\\,\\\\mathrm{m/s}\\\\) en \\\\(8\\\\,\\\\mathrm{s}\\\\). Quelle est son accélération ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(a = \\\\frac{v - v_0}{t}\\\\). \\\\(a = \\\\frac{16 - 0}{8} = 2\\\\,\\\\mathrm{m/s^2}\\\\).",
      "answers": [
        {
          "answer_title": "2 m/s^2",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "1 m/s^2",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "4 m/s^2",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "8 m/s^2",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 13,
      "question_title": "Un objet se déplace à \\\\(18\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(25\\\\,\\\\mathrm{s}\\\\). Quelle distance parcourt-il ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRU, \\\\(x = v t = 18 \\\\times 25 = 450\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "450 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "400 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "500 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "300 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 14,
      "question_title": "Un objet part de \\\\(x_0 = 0\\\\) avec \\\\(v_0 = 2\\\\,\\\\mathrm{m/s}\\\\) et accélère à \\\\(4\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(3\\\\,\\\\mathrm{s}\\\\). Quelle est sa position finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRUA, \\\\(x = 0 + 2 \\\\times 3 + 0,5 \\\\times 4 \\\\times 9 = 6 + 18 = 24\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "24 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "18 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "12 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "30 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 15,
      "question_title": "Un objet lancé à \\\\(8\\\\,\\\\mathrm{m/s}\\\\) subit une accélération de \\\\(-2\\\\,\\\\mathrm{m/s^2}\\\\). Quelle distance parcourt-il avant de s’arrêter ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(x = \\\\frac{0^2 - 8^2}{2 \\\\times -2} = \\\\frac{-64}{-4} = 16\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "16 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "8 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "32 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "4 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 16,
      "question_title": "Un objet part du repos et accélère à \\\\(0,5\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(12\\\\,\\\\mathrm{s}\\\\). Quelle distance parcourt-il ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRUA, \\\\(x = 0 + 0 + 0,5 \\\\times 0,5 \\\\times 144 = 0,25 \\\\times 144 = 36\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "36 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "24 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "72 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "12 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 17,
      "question_title": "Un objet a une vitesse initiale de \\\\(5\\\\,\\\\mathrm{m/s}\\\\) et accélère à \\\\(1\\\\,\\\\mathrm{m/s^2}\\\\) pendant \\\\(10\\\\,\\\\mathrm{s}\\\\). Quelle est sa vitesse finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Vitesse finale : \\\\(v = 5 + 1 \\\\times 10 = 15\\\\,\\\\mathrm{m/s}\\\\).",
      "answers": [
        {
          "answer_title": "15 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "10 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "5 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "20 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 18,
      "question_title": "Un objet part de \\\\(x_0 = 3\\\\,\\\\mathrm{m}\\\\), avance à \\\\(7\\\\,\\\\mathrm{m/s}\\\\) pendant \\\\(5\\\\,\\\\mathrm{s}\\\\). Quelle est sa position finale ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "En MRU, \\\\(x = 3 + 7 \\\\times 5 = 3 + 35 = 38\\\\,\\\\mathrm{m}\\\\).",
      "answers": [
        {
          "answer_title": "38 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "35 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "28 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "10 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 19,
      "question_title": "Un objet lancé à \\\\(12\\\\,\\\\mathrm{m/s}\\\\) subit une accélération de \\\\(-3\\\\,\\\\mathrm{m/s^2}\\\\). Combien de temps met-il pour s’arrêter ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(v = v_0 + a t\\\\). \\\\(0 = 12 - 3t\\\\) donc \\\\(t = 4\\\\,\\\\mathrm{s}\\\\).",
      "answers": [
        {
          "answer_title": "4 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "3 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "6 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "2 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 20,
      "question_title": "Un objet part du repos et atteint \\\\(25\\\\,\\\\mathrm{m/s}\\\\) en \\\\(5\\\\,\\\\mathrm{s}\\\\). Quelle est son accélération ?",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "On utilise \\\\(a = \\\\frac{v - v_0}{t}\\\\). \\\\(a = \\\\frac{25 - 0}{5} = 5\\\\,\\\\mathrm{m/s^2}\\\\).",
      "answers": [
        {
          "answer_title": "5 m/s^2",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "10 m/s^2",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "2,5 m/s^2",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "1 m/s^2",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    }
  ]
}

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Salut! 👋 Pose ta question à l'IA ou telecharge une image (photo ou screenshot) de ton exercice. Mwen pale kreyòl tou.