Travail Et Energie — Quiz — Chute Libre

✅ Quiz : Chute Libre

Ce quiz contient 20 questions.

Note : Placeholder pour valider la structure. Le JSON converti est conservé ci-dessous pour l’import final des vraies questions Tutor LMS.

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{
  "quiz_title": "Chute Libre",
  "quiz_slug": "05_chute_libre_quiz",
  "quiz_description": "Quiz Edu509 : Chute Libre",
  "quiz_settings": {
    "time_limit": {
      "time_value": 0,
      "time_type": "minutes"
    },
    "hide_quiz_time_display": false,
    "attempts_allowed": 0,
    "passing_grade": 70,
    "max_questions_for_answer": 0,
    "questions_order": "rand",
    "hide_question_number_overview": false,
    "short_answer_characters_limit": 200
  },
  "questions": [
    {
      "question_order": 1,
      "question_title": "Un objet est lâché sans vitesse initiale d'une hauteur de \\\\( h = 10{,}0\\\\ \\\\mathrm{m} \\\\). Quel est le temps de chute ? (Prendre \\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de chute est \\\\( t = \\\\sqrt{\\\\frac{2h}{g}} = \\\\sqrt{\\\\frac{2 \\\\times 10,0}{10}} = \\\\sqrt{2,0} = 1,4\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "1,0 s",
          "is_correct": false,
          "answer_order": 1
        },
        {
          "answer_title": "1,4 s",
          "is_correct": true,
          "answer_order": 2
        },
        {
          "answer_title": "2,0 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "3,2 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 2,
      "question_title": "Quelle est la vitesse juste avant d’atteindre le sol pour un objet lâché de \\\\( 18{,}0\\\\ \\\\mathrm{m} \\\\) ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{2gh} = \\\\sqrt{2 \\\\times 10 \\\\times 18,0} = \\\\sqrt{360} = 19,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "18,0 m/s",
          "is_correct": false,
          "answer_order": 1
        },
        {
          "answer_title": "12,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "6,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "19,0 m/s",
          "is_correct": true,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 3,
      "question_title": "Un élève lance une balle verticalement vers le bas avec \\\\( v_0 = 4,0\\\\ \\\\mathrm{m/s} \\\\) depuis \\\\( 9,0\\\\ \\\\mathrm{m} \\\\) de haut. Quelle est la vitesse juste avant l’impact ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{v_0^2 + 2gh} = \\\\sqrt{(4,0)^2 + 2 \\\\times 10 \\\\times 9,0} = \\\\sqrt{16 + 180} = \\\\sqrt{196} = 14,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "14,0 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "13,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "12,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "10,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 4,
      "question_title": "Un objet est lancé verticalement vers le haut avec \\\\( v_0 = 8,0\\\\ \\\\mathrm{m/s} \\\\). Quelle est la hauteur maximale atteinte ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La hauteur maximale est \\\\( h_{\\\\mathrm{max}} = \\\\frac{v_0^2}{2g} = \\\\frac{(8,0)^2}{2 \\\\times 10} = \\\\frac{64}{20} = 3,2\\\\ \\\\mathrm{m} \\\\).",
      "answers": [
        {
          "answer_title": "3,2 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "2,4 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "4,0 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "6,4 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 5,
      "question_title": "Un objet est lâché d’une hauteur de \\\\( 45,0\\\\ \\\\mathrm{m} \\\\). Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{2gh} = \\\\sqrt{2 \\\\times 10 \\\\times 45,0} = \\\\sqrt{900} = 30,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "30,0 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "20,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "15,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "45,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 6,
      "question_title": "Un objet est lancé vers le haut avec \\\\( v_0 = 10,0\\\\ \\\\mathrm{m/s} \\\\). Combien de temps met-il pour atteindre la hauteur maximale ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de montée est \\\\( t = \\\\frac{v_0}{g} = \\\\frac{10,0}{10} = 1,0\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "1,0 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "2,0 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "0,5 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "5,0 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 7,
      "question_title": "Un objet est lâché sans vitesse initiale d’une hauteur de \\\\( 20,0\\\\ \\\\mathrm{m} \\\\). Quelle est la durée de la chute ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de chute est \\\\( t = \\\\sqrt{\\\\frac{2h}{g}} = \\\\sqrt{\\\\frac{2 \\\\times 20,0}{10}} = \\\\sqrt{4,0} = 2,0\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "2,0 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "4,0 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "1,4 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "3,0 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 8,
      "question_title": "Un objet est lancé vers le haut avec \\\\( v_0 = 6,0\\\\ \\\\mathrm{m/s} \\\\). Quelle est la hauteur maximale atteinte ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La hauteur maximale est \\\\( h_{\\\\mathrm{max}} = \\\\frac{v_0^2}{2g} = \\\\frac{(6,0)^2}{2 \\\\times 10} = \\\\frac{36}{20} = 1,8\\\\ \\\\mathrm{m} \\\\).",
      "answers": [
        {
          "answer_title": "1,8 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "3,6 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "0,6 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "2,4 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 9,
      "question_title": "Un objet est lancé verticalement vers le bas avec \\\\( v_0 = 5,0\\\\ \\\\mathrm{m/s} \\\\) depuis \\\\( 15,0\\\\ \\\\mathrm{m} \\\\) de haut. Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{v_0^2 + 2gh} = \\\\sqrt{(5,0)^2 + 2 \\\\times 10 \\\\times 15,0} = \\\\sqrt{25 + 300} = \\\\sqrt{325} = 17,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "20,0 m/s",
          "is_correct": false,
          "answer_order": 1
        },
        {
          "answer_title": "15,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "17,0 m/s",
          "is_correct": true,
          "answer_order": 3
        },
        {
          "answer_title": "10,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 10,
      "question_title": "Un objet est lâché sans vitesse initiale d’une hauteur de \\\\( 5,0\\\\ \\\\mathrm{m} \\\\). Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{2gh} = \\\\sqrt{2 \\\\times 10 \\\\times 5,0} = \\\\sqrt{100} = 10,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "10,0 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "5,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "7,1 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "2,2 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 11,
      "question_title": "Un objet est lancé vers le haut avec \\\\( v_0 = 16,0\\\\ \\\\mathrm{m/s} \\\\). Quelle est la hauteur maximale atteinte ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La hauteur maximale est \\\\( h_{\\\\mathrm{max}} = \\\\frac{v_0^2}{2g} = \\\\frac{(16,0)^2}{2 \\\\times 10} = \\\\frac{256}{20} = 12,8\\\\ \\\\mathrm{m} \\\\).",
      "answers": [
        {
          "answer_title": "12,8 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "8,0 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "25,6 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "16,0 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 12,
      "question_title": "Un objet est lancé verticalement vers le haut avec \\\\( v_0 = 20,0\\\\ \\\\mathrm{m/s} \\\\). Quel est le temps total de vol jusqu’à ce qu’il retombe au sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de montée est \\\\( t = \\\\frac{v_0}{g} = \\\\frac{20,0}{10} = 2,0\\\\ \\\\mathrm{s} \\\\). Le temps total est \\\\( 2 \\\\times 2,0 = 4,0\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "2,0 s",
          "is_correct": false,
          "answer_order": 1
        },
        {
          "answer_title": "4,0 s",
          "is_correct": true,
          "answer_order": 2
        },
        {
          "answer_title": "1,0 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "5,0 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 13,
      "question_title": "Un objet est lâché sans vitesse initiale d’une hauteur de \\\\( 2,0\\\\ \\\\mathrm{m} \\\\). Quelle est la durée de la chute ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de chute est \\\\( t = \\\\sqrt{\\\\frac{2h}{g}} = \\\\sqrt{\\\\frac{2 \\\\times 2,0}{10}} = \\\\sqrt{0,4} = 0,6\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "0,6 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "1,0 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "2,0 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "0,2 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 14,
      "question_title": "Un objet est lancé vers le bas avec \\\\( v_0 = 2,0\\\\ \\\\mathrm{m/s} \\\\) depuis \\\\( 8,0\\\\ \\\\mathrm{m} \\\\) de haut. Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{v_0^2 + 2gh} = \\\\sqrt{(2,0)^2 + 2 \\\\times 10 \\\\times 8,0} = \\\\sqrt{4 + 160} = \\\\sqrt{164} = 13,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "13,0 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "12,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "10,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "8,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 15,
      "question_title": "Un objet est lancé vers le haut avec \\\\( v_0 = 14,0\\\\ \\\\mathrm{m/s} \\\\). Quelle est la hauteur maximale atteinte ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La hauteur maximale est \\\\( h_{\\\\mathrm{max}} = \\\\frac{v_0^2}{2g} = \\\\frac{(14,0)^2}{2 \\\\times 10} = \\\\frac{196}{20} = 9,8\\\\ \\\\mathrm{m} \\\\).",
      "answers": [
        {
          "answer_title": "9,8 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "7,0 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "14,0 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "19,6 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 16,
      "question_title": "Un objet est lâché sans vitesse initiale d’une hauteur de \\\\( 50,0\\\\ \\\\mathrm{m} \\\\). Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{2gh} = \\\\sqrt{2 \\\\times 10 \\\\times 50,0} = \\\\sqrt{1000} = 31,6\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "31,6 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "25,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "10,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "50,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 17,
      "question_title": "Un objet est lancé verticalement vers le haut avec \\\\( v_0 = 18,0\\\\ \\\\mathrm{m/s} \\\\). Quel est le temps total de vol jusqu’à ce qu’il retombe au sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de montée est \\\\( t = \\\\frac{v_0}{g} = \\\\frac{18,0}{10} = 1,8\\\\ \\\\mathrm{s} \\\\). Le temps total est \\\\( 2 \\\\times 1,8 = 3,6\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "3,6 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "1,8 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "2,8 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "4,0 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 18,
      "question_title": "Un objet est lâché sans vitesse initiale d’une hauteur de \\\\( 8,0\\\\ \\\\mathrm{m} \\\\). Quelle est la durée de la chute ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "Le temps de chute est \\\\( t = \\\\sqrt{\\\\frac{2h}{g}} = \\\\sqrt{\\\\frac{2 \\\\times 8,0}{10}} = \\\\sqrt{1,6} = 1,3\\\\ \\\\mathrm{s} \\\\).",
      "answers": [
        {
          "answer_title": "1,3 s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "2,0 s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "0,8 s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "1,8 s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 19,
      "question_title": "Un objet est lancé vers le bas avec \\\\( v_0 = 7,0\\\\ \\\\mathrm{m/s} \\\\) depuis \\\\( 12,0\\\\ \\\\mathrm{m} \\\\) de haut. Quelle est la vitesse juste avant d’atteindre le sol ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La vitesse finale est \\\\( v = \\\\sqrt{v_0^2 + 2gh} = \\\\sqrt{(7,0)^2 + 2 \\\\times 10 \\\\times 12,0} = \\\\sqrt{49 + 240} = \\\\sqrt{289} = 17,0\\\\ \\\\mathrm{m/s} \\\\).",
      "answers": [
        {
          "answer_title": "17,0 m/s",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "14,0 m/s",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "12,0 m/s",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "19,0 m/s",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    },
    {
      "question_order": 20,
      "question_title": "Un objet est lancé verticalement vers le haut avec \\\\( v_0 = 5,0\\\\ \\\\mathrm{m/s} \\\\). Quelle est la hauteur maximale atteinte ? (\\\\( g = 10\\\\ \\\\mathrm{m/s^2} \\\\))",
      "question_type": "single_choice",
      "question_mark": 1,
      "answer_required": true,
      "randomize_question": false,
      "show_question_mark": true,
      "question_description": "",
      "question_explanation": "La hauteur maximale est \\\\( h_{\\\\mathrm{max}} = \\\\frac{v_0^2}{2g} = \\\\frac{(5,0)^2}{2 \\\\times 10} = \\\\frac{25}{20} = 1,25\\\\ \\\\mathrm{m} \\\\).",
      "answers": [
        {
          "answer_title": "1,25 m",
          "is_correct": true,
          "answer_order": 1
        },
        {
          "answer_title": "2,5 m",
          "is_correct": false,
          "answer_order": 2
        },
        {
          "answer_title": "0,5 m",
          "is_correct": false,
          "answer_order": 3
        },
        {
          "answer_title": "5,0 m",
          "is_correct": false,
          "answer_order": 4
        }
      ]
    }
  ]
}

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Salut! 👋 Pose ta question à l'IA ou telecharge une image (photo ou screenshot) de ton exercice. Mwen pale kreyòl tou.