Ecrit par ✅ Quiz : Electro Aimant
Ce quiz contient 20 questions.
Note : Placeholder pour valider la structure. Le JSON converti est conservé ci-dessous pour l’import final des vraies questions Tutor LMS.
JSON Tutor LMS-ready
{
"quiz_title": "Electro Aimant",
"quiz_slug": "02_electro_aimant_quiz",
"quiz_description": "Quiz Edu509 : Electro Aimant",
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"questions": [
{
"question_order": 1,
"question_title": "Quelle est la formule correcte pour calculer le champ magnétique à l’intérieur d’un solénoïde long ?",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "La formule correcte pour le champ magnétique à l’intérieur d’un solénoïde long est \\\\( B = \\\\mu_0 \\\\mu_r \\\\frac{N}{l} I \\\\), où \\\\( N \\\\) est le nombre de spires, \\\\( l \\\\) la longueur, \\\\( I \\\\) le courant, \\\\( \\\\mu_0 \\\\) la perméabilité du vide et \\\\( \\\\mu_r \\\\) la perméabilité relative.",
"answers": [
{
"answer_title": "\\\\( B = \\\\mu_0 \\\\mu_r \\\\frac{N}{l} I \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( B = \\\\mu_0 \\\\frac{I}{N} l \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( B = \\\\mu_0 \\\\mu_r N l I \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( B = \\\\mu_0 \\\\mu_r \\\\frac{l}{N} I \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 2,
"question_title": "Une bobine de \\\\( N = 1000 \\\\) spires, de longueur \\\\( l = 0{,}50 \\\\mathrm{m} \\\\), parcourue par un courant \\\\( I = 2{,}0 \\\\mathrm{A} \\\\), sans noyau ferromagnétique (\\\\( \\\\mu_r = 1 \\\\)), produit un champ magnétique de :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B = 5{,}0 \\\\mathrm{mT} = 0{,}005 \\\\mathrm{T} \\\\). Les deux réponses sont équivalentes.",
"answers": [
{
"answer_title": "\\\\( 5{,}0 \\\\mathrm{mT} \\\\)",
"is_correct": false,
"answer_order": 1
},
{
"answer_title": "\\\\( 0{,}50 \\\\mathrm{mT} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 50 \\\\mathrm{mT} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}005 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 4
}
]
},
{
"question_order": 3,
"question_title": "Quel paramètre augmente le plus fortement le champ magnétique d’un électro-aimant ?",
"question_type": "multiple_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le champ magnétique est proportionnel à \\\\( N \\\\), \\\\( I \\\\), et \\\\( \\\\mu_r \\\\), mais inversement proportionnel à \\\\( l \\\\).",
"answers": [
{
"answer_title": "Augmenter le nombre de spires \\\\( N \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Augmenter la longueur \\\\( l \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Diminuer le courant \\\\( I \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Utiliser un noyau avec une perméabilité relative \\\\( \\\\mu_r \\\\) plus grande",
"is_correct": true,
"answer_order": 4
}
]
},
{
"question_order": 4,
"question_title": "Pour une bobine de \\\\( N = 500 \\\\), \\\\( l = 0{,}25 \\\\mathrm{m} \\\\), \\\\( I = 1{,}5 \\\\mathrm{A} \\\\), et \\\\( \\\\mu_r = 2000 \\\\), le champ magnétique à l’intérieur est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B \\\\approx 7{,}5 \\\\mathrm{T} \\\\) selon la formule et les valeurs fournies.",
"answers": [
{
"answer_title": "\\\\( 7{,}5 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 0{,}75 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 75 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}075 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 5,
"question_title": "La perméabilité relative \\\\( \\\\mu_r \\\\) d’un noyau en fer doux est typiquement :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le fer doux a une perméabilité relative très supérieure à 1, ce qui amplifie le champ magnétique.",
"answers": [
{
"answer_title": "Beaucoup plus grande que 1",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Égale à 1",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Négative",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Toujours inférieure à 1",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 6,
"question_title": "Si on double le courant \\\\( I \\\\) dans un solénoïde, le champ magnétique \\\\( B \\\\) :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le champ magnétique est proportionnel au courant : \\\\( B \\\\propto I \\\\).",
"answers": [
{
"answer_title": "Double",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Est divisé par deux",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Reste inchangé",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Est multiplié par quatre",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 7,
"question_title": "Dans la formule \\\\( B = \\\\mu_0 \\\\mu_r \\\\frac{N}{l} I \\\\), si on réduit la longueur \\\\( l \\\\) de moitié, que devient \\\\( B \\\\) ?",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le champ magnétique est inversement proportionnel à la longueur : si \\\\( l \\\\) diminue de moitié, \\\\( B \\\\) double.",
"answers": [
{
"answer_title": "Il double",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Il est divisé par deux",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Il ne change pas",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Il est multiplié par quatre",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 8,
"question_title": "Le champ magnétique à l’extérieur d’un solénoïde long est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "À l’extérieur d’un solénoïde long, le champ magnétique est négligeable.",
"answers": [
{
"answer_title": "Quasiment nul",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Très intense",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Égal à celui de l’intérieur",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Toujours supérieur à 1 T",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 9,
"question_title": "Pour une bobine de \\\\( N = 600 \\\\), \\\\( l = 0{,}30 \\\\mathrm{m} \\\\), \\\\( I = 1{,}8 \\\\mathrm{A} \\\\), \\\\( \\\\mu_r = 1200 \\\\), le champ magnétique est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B = 5{,}4 \\\\mathrm{T} \\\\) avec les valeurs fournies.",
"answers": [
{
"answer_title": "\\\\( 5{,}4 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 0{,}54 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 54 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}054 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 10,
"question_title": "Quel est le rôle principal du noyau en fer doux dans un électro-aimant ?",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le noyau en fer doux concentre les lignes de champ et augmente fortement le champ magnétique.",
"answers": [
{
"answer_title": "Concentrer et amplifier le champ magnétique",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Réduire le courant électrique",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Augmenter la résistance électrique",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Diminuer le nombre de spires",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 11,
"question_title": "Pour une bobine de \\\\( N = 800 \\\\), \\\\( l = 0{,}40 \\\\mathrm{m} \\\\), \\\\( I = 2{,}5 \\\\mathrm{A} \\\\), \\\\( \\\\mu_r = 1000 \\\\), le champ magnétique est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B = 6{,}3 \\\\mathrm{T} \\\\) avec les valeurs fournies.",
"answers": [
{
"answer_title": "\\\\( 6{,}3 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 0{,}63 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 63 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}063 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 12,
"question_title": "Si le courant dans une bobine passe de 0 à \\\\( 3{,}0 \\\\mathrm{A} \\\\) en \\\\( 0{,}10 \\\\mathrm{s} \\\\), et que la variation du flux magnétique total est \\\\( 1{,}13 \\\\times 10^{-2} \\\\mathrm{Wb} \\\\), pour \\\\( N = 1200 \\\\), la fém induite est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "La fém induite est \\\\( e = -N \\\\frac{\\\\Delta \\\\Phi}{\\\\Delta t} = -135{,}6 \\\\mathrm{V} \\\\).",
"answers": [
{
"answer_title": "\\\\( -135{,}6 \\\\mathrm{V} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( +135{,}6 \\\\mathrm{V} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( -13{,}6 \\\\mathrm{V} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( +13{,}6 \\\\mathrm{V} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 13,
"question_title": "Pour augmenter la force d’un électro-aimant, on peut :",
"question_type": "multiple_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "La force dépend du champ magnétique, qui augmente avec \\\\( N \\\\), \\\\( \\\\mu_r \\\\), et \\\\( I \\\\), et diminue avec \\\\( l \\\\).",
"answers": [
{
"answer_title": "Augmenter le nombre de spires \\\\( N \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Augmenter la perméabilité relative \\\\( \\\\mu_r \\\\)",
"is_correct": true,
"answer_order": 2
},
{
"answer_title": "Diminuer la longueur \\\\( l \\\\)",
"is_correct": true,
"answer_order": 3
},
{
"answer_title": "Diminuer le courant \\\\( I \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 14,
"question_title": "La constante \\\\( \\\\mu_0 \\\\) (perméabilité du vide) vaut :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "La perméabilité du vide est \\\\( 4\\\\pi \\\\times 10^{-7} \\\\mathrm{T\\\\cdot m/A} \\\\).",
"answers": [
{
"answer_title": "\\\\( 4\\\\pi \\\\times 10^{-7} \\\\mathrm{T\\\\cdot m/A} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 9{,}8 \\\\mathrm{m/s^2} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 8{,}85 \\\\times 10^{-12} \\\\mathrm{F/m} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 1{,}6 \\\\times 10^{-19} \\\\mathrm{C} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 15,
"question_title": "Si on utilise de l’air comme noyau (\\\\( \\\\mu_r = 1 \\\\)), le champ magnétique d’un solénoïde est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le champ magnétique est beaucoup plus faible sans noyau ferromagnétique, car \\\\( \\\\mu_r = 1 \\\\).",
"answers": [
{
"answer_title": "Plus faible qu’avec un noyau en fer doux",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Plus fort qu’avec un noyau en fer doux",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Toujours nul",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Indépendant de \\\\( \\\\mu_r \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 16,
"question_title": "Dans la loi de Faraday, la fém induite dans une bobine est proportionnelle :",
"question_type": "multiple_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "La fém induite est \\\\( e = -N \\\\frac{\\\\Delta \\\\Phi}{\\\\Delta t} \\\\), donc proportionnelle à \\\\( N \\\\) et à la variation du flux.",
"answers": [
{
"answer_title": "Au nombre de spires \\\\( N \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "À la variation du flux magnétique",
"is_correct": true,
"answer_order": 2
},
{
"answer_title": "À la résistance du fil",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "À la longueur de la bobine",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 17,
"question_title": "Pour une bobine de \\\\( N = 1200 \\\\), \\\\( l = 0{,}60 \\\\mathrm{m} \\\\), \\\\( I = 3{,}0 \\\\mathrm{A} \\\\), \\\\( \\\\mu_r = 1500 \\\\), le champ magnétique final est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B = 11{,}3 \\\\mathrm{T} \\\\) avec les valeurs fournies.",
"answers": [
{
"answer_title": "\\\\( 11{,}3 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 1{,}13 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 113 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}113 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 18,
"question_title": "L’unité du champ magnétique \\\\( B \\\\) dans le Système International est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "L’unité du champ magnétique est le Tesla (T).",
"answers": [
{
"answer_title": "Tesla (T)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Ampère (A)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Weber (Wb)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Volt (V)",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 19,
"question_title": "Si on triple le nombre de spires \\\\( N \\\\) d’un solénoïde, le champ magnétique :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le champ magnétique est proportionnel au nombre de spires \\\\( N \\\\).",
"answers": [
{
"answer_title": "Est multiplié par trois",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "Est divisé par trois",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "Ne change pas",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "Est multiplié par neuf",
"is_correct": false,
"answer_order": 4
}
]
},
{
"question_order": 20,
"question_title": "Pour une bobine de \\\\( N = 400 \\\\), \\\\( l = 0{,}20 \\\\mathrm{m} \\\\), \\\\( I = 2{,}0 \\\\mathrm{A} \\\\), \\\\( \\\\mu_r = 800 \\\\), le champ magnétique est :",
"question_type": "single_choice",
"question_mark": 1,
"answer_required": true,
"randomize_question": false,
"show_question_mark": true,
"question_description": "",
"question_explanation": "Le calcul donne \\\\( B = 4{,}0 \\\\mathrm{T} \\\\) avec les valeurs fournies.",
"answers": [
{
"answer_title": "\\\\( 4{,}0 \\\\mathrm{T} \\\\)",
"is_correct": true,
"answer_order": 1
},
{
"answer_title": "\\\\( 0{,}40 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 2
},
{
"answer_title": "\\\\( 40 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 3
},
{
"answer_title": "\\\\( 0{,}004 \\\\mathrm{T} \\\\)",
"is_correct": false,
"answer_order": 4
}
]
}
]
}